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  #2  
Old December 24th, 2013, 11:54 AM
Super Moderator
 
Join Date: Jun 2013
Default Re: Patni Computer Solutions Placement Papers

You are looking for the Patni Computer Solutions Placement Papers i am giving here:

1. IKBUTA
1) $8@721
2) ?8@72?
3) %8@72%
4) ?8@72%
5) None of these

2. EMPRJH
1) 9653#4
2) ?9653#
3) %653#%
4) ?653#?
5) None of these

3. IPAUHM
1) ?5174?
2) %5174%
3) $51746
4) $51476
5) None of these

4. RFHKJA
1) 3©48#1
2) 483©#1
3) ?©48#?
4) %©48%
5) None of these

5. TMRBFJ
1) ?63@©?
2) %63@©%
3) 236@©#
4) 263@©#
5) None of these

6.KTJUFA
1) 82#7©1
2) ?2#7©?
3) %2#7©%
4) $2#7©1
5) None of these

7. UMBKPE
1) ?6@85?
2) 76@85©
3) ?6@85©
4) 76@85%
5) None of these

8. Find the approximate value of the following equation.
8149.72 + 6935.25 – 1756.79 – 3567.42 = ?
1) 9750
2) 9760
3) 9765
4) 9755
5) 9770

9. A milkman buys some milk. If he sells it at Rs 5 per litre, he loses Rs 200. But when he sells it at Rs 6 per litre, he gains Rs 150. How much milk did he purchase?
1) 50 litres
2) 31 litres
3) 350 litres
4) 200 litres
5) None of these

For detailed paper here is attachment;
Attached Files Available for Download
File Type: doc Patni Placement Papers.doc (29.0 KB, 41 views)
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  #3  
Old October 10th, 2015, 09:12 AM
Unregistered
Guest
 
Default Re: Patni Computer Solutions Placement Papers

hii sir, I wanted to get a job in Paptni Computer Solutions can you tell me about their process of selection and also provide me the Aptitude question paper?
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  #4  
Old October 10th, 2015, 09:17 AM
Super Moderator
 
Join Date: Dec 2012
Default Re: Patni Computer Solutions Placement Papers

As you wanted to get Job in patni Computer Solution let me tell you that there placement drive consist of three Rounds they are :
Apptitude Test as first Round
Technical Round
Interview
the selection will be based on the performance of the both Three rounds and the interview .
As you aski8ng for the Aptitude question paper here I am providng you the question paper the questions are as follow:
1)A train covers a distance in 50 min ,if it runs at a speed
of 48kmph on an average.The speed at which the train must run
to reduce the time of journey to 40min will be.

1. Solution::
Time=50/60 hr=5/6hr
Speed=48mph
distance=S*T=48*5/6=40km
time=40/60hr=2/3hr
New speed = 40* 3/2 kmph= 60kmph

2)Vikas can cover a distance in 1hr 24min by covering 2/3 of
the distance at 4 kmph and the rest at 5kmph.the total
distance is?

2. Solution::
Let total distance be S
total time=1hr24min
A to T :: speed=4kmph
diistance=2/3S
T to S :: speed=5km
distance=1-2/3S=1/3S
21/15 hr=2/3 S/4 + 1/3s /5
84=14/3S*3
S=84*3/14*3
= 6km

3)walking at ¾ of his usual speed ,a man is late by 2 ½ hr.
the usual time is.

3. Solution::
Usual speed = S
Usual time = T
Distance = D
New Speed is ¾ S
New time is 4/3 T
4/3 T – T = 5/2
T=15/2 = 7 ½

4)A man covers a distance on scooter .had he moved 3kmph
faster he would have taken 40 min less. If he had moved
2kmph slower he would have taken 40min more.the distance is.

4.Solution::
Let distance = x m
Usual rate = y kmph
x/y – x/y+3 = 40/60 hr
2y(y+3) = 9x ————–1
x/y-2 – x/y = 40/60 hr y(y-2) = 3x —————–2
divide 1 & 2 equations
by solving we get x = 40

5)Excluding stoppages,the speed of the bus is 54kmph and
including stoppages,it is 45kmph.for how many min does the bus
stop per hr.

Solution::
Due to stoppages,it covers 9km less.
time taken to cover 9 km is [9/54 *60] min = 10min

6)Two boys starting from the same place walk at a rate of
5kmph and 5.5kmph respectively.wht time will they take to be
8.5km apart, if they walk in the same direction

6.Solution::
The relative speed of the boys = 5.5kmph – 5kmph = 0.5 kmph
Distance between them is 8.5 km
Time= 8.5km / 0.5 kmph = 17 hrs

7)2 trains starting at the same time from 2 stations 200km
apart and going in opposite direction cross each other ata
distance of 110km from one of the stations.what is the ratio of
their speeds.

7. Solution::
In same time ,they cover 110km & 90 km respectively
so ratio of their speed =110:90 = 11:9

8)Two trains start from A & B and travel towards each other at
speed of 50kmph and 60kmph resp. At the time of the meeting the
second train has traveled 120km more than the first.the distance
between them

Solution::
Let the distance traveled by the first train be x km
then distance covered by the second train is x + 120km
x/50 = x+120 / 60
x= 600
so the distance between A & B is x + x + 120 = 1320 km

9)A thief steals a ca r at 2.30pm and drives it at 60kmph.the
theft is discovered at 3pm and the owner sets off in another car
at 75kmph when will he overtake the thief

Solution::
Let the thief is overtaken x hrs after 2.30pm
distance covered by the thief in x hrs = distance covered by
the owner in x-1/2 hr
60x = 75 ( x- ½)
x= 5/2 hr
thief is overtaken at 2.30 pm + 2 ½ hr = 5 pm





Rest of the questions you may found in the file given below:
Attached Files Available for Download
File Type: pdf Patni Computer Solutions Placement Papers.pdf (195.3 KB, 31 views)
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