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Old May 23rd, 2014, 04:17 PM
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Default Re: CISCO previous year placement papers

As you want to get the Computer Information System Company previous year placement papers so here is the information of the same for you:

1 What is the probability of getting at least one six in a single throw of three unbiased dice?

(1) 1 / 6
(2) 125 / 216
(3) 1 / 36
(4) 81 / 216
(5) 91 / 216

Correct choice is (5) and Correct Answer is 91 / 216
Explanatory Answer
Every die has got six sides. Each of the sides is numbered from 1 to 6.
When a single unbiased die is thrown you can have six possible outcomes.
When two dice are thrown simultaneously, the total number of outcomes will be 6 * 6 = 36
Similarly, when three dice are thrown simultaneously, the total number of outcomes will be 6*6*6=216.
We need to find out the number of cases in which at least one of the facing sides shows 6.
At least one means - either one dice or two dice or all three.

Case 1: Let us take the easiest case first - all three dice showing '6' - There is only one such possibility.

Case 2: The number of cases in which two of the dice show 6 and one of them is a different number.
For eg an event like 6 6 5 will be one of the outcomes for case 2.

As two of the dice show '6' , it can happen in only one way. The third die shows a different number, a number other than 6, and it can be any of the 5 other numbers. Therefore, there will 5 possible options i.e. (1, 6, 6), (2, 6, 6), (3, 6, 6), (4, 6, 6), (5, 6, 6).

However, each of these possibilities can have three different arrangements depending upon where the third different digit appears. For example take (1, 6, 6) case - it will have three options (1, 6, 6), (6, 1, 6), (6, 6, 1).

Therefore, the total number of events in which 2 of the dice will show '6' and one will show a different number = 5*3 = 15 cases.

Case 3: When only one of the die shows '6' and the other two show numbers other than '6'.

The die showing '6' has only one option. The other two dice can have any of the '5' options. Therefore, the total number of possibilities = 1*5*5 = 25.

However, the die showing '6' can either be the first die or the second die or the third die.

Therefore, there are a total of 25 * 3 = 75 possibilities.

Total possible outcomes where at least one die shows '6' = Case 1 + Case 2 + Case 3 = 1 + 15 +75 = 91.

Therefore, the required probability = 91/216

Alternate approach:

Find the number of cases in which none of the digits show a '6'.

i.e. all three dice show a number other than '6', 5 * 5 *5 = 125 cases.

Total possible outcomes when three dice are thrown = 216.

The number of outcomes in which at least one die shows a '6' = Total possible outcomes when three dice are thrown - Number of outcomes in which none of them show '6'.

= 216 - 125 = 91.

The required probability = 91/216

2 When two dice are thrown simultaneously, what is the probability that the sum of the two numbers that turn up is less than 11?

(1) 5 / 6
(2) 11 / 12
(3) 1 / 6
(4) 1 / 12
Correct Answer - (2)
Solution:

Instead of finding the probability of this event directly, we will find the probability of the non-occurrence of this event and subtract it from 1 to get the required probability.

Combination whose sum of 12 is (6,6)

Combinations whose sum of 11 is (5,6), (6,5).

Therefore, there are totally 3 occurrences out of 36 occurrences that satisfy the given condition.

Probability whose sum of two numbers is greater than or equal to 11 = 3 / 36 = 1 / 12.

Hence probability whose sum of two numbers is lesser than 11 = 1 - 1 / 12 = 11 / 12.

3 The average monthly salary of 12 workers and 3 managers in a factory was Rs. 600. When one of the manager whose salary was Rs. 720, was replaced with a new manager, then the average salary of the team went down to 580. What is the salary of the new manager?
Rs 570
Rs 420
Rs 690
Rs 640
Rs 610
Correct Answer - Rs 420. Choice (2)

Explanatory Answer

The total salary amount = 15 * 600 = 9000

The salary of the exiting manager = 720.

Therefore, the salary of 12 workers and the remaining 2 managers = 9000 - 720 = 8280

When a new manager joins, the new average salary drops to Rs.580 for the total team of 15 of them.

The total salary for the 15 people i.e., 12 workers, 2 old managers and 1 new manager = 580 *15 = 8700

Therefore, the salary of the new manager is 9000 - 8700 = 300 less than that of the old manager who left the company, which is equal to 720 - 300 = 420.

An alternative method of doing the problem is as follows:

The average salary dropped by Rs.20 for 15 of them. Therefore, the overall salary has dropped by 15*20 = 300.

Therefore, the new manager's salary should be Rs.300 less than that of the old manager = 720 - 300 = 420.

Correct answer choice (2)

4 If the letters of the word CHASM are rearranged to form 5 letter words such that none of the word repeat and the results arranged in ascending order as in a dictionary what is the rank of the word CHASM?

(1) 24
(2) 31
(3) 32
(4) 30
Correct Answer - (3)
Solution:

The 5 letter word can be rearranged in 5! Ways = 120 without any of the letters repeating.

The first 24 of these words will start with A.

Then the 25th word will start will CA _ _ _. The remaining 3 letters can be rearranged in 3! Ways = 6. i.e. 6 words exist that start with CA.

The next word starts with CH and then A, i.e., CHA _ _. The first of the words will be CHAMS. The next word will be CHASM.

Therefore, the rank of CHASM will be 24 + 6 + 2 = 32.

5 The time in a clock is 20 minute past 2. Find the angle between the hands of the clock.
(1) 60 degrees
(2) 120 degrees
(3) 45 degrees
(4) 50 degrees
Correct choice (4). Correct Answer - 50 degrees
Solution:

Time is 2:20. Position of the hands: Hour hand at 2 (nearly).
Minute hand at 4
Angle between 2 and 4 is 60 degrees [(360/12) * (4-2)]
Angle made by the hour hand in 20 minutes is 10 degrees, since it turns through ½ degrees in a minute.
Therefore, angle between the hands is 60 degrees - 10 degrees = 50 degrees

6 .A 12% stock yielding 10% is quoted at:

A.Rs. 83.33
B.Rs. 110
C.Rs. 112
D.Rs. 120
Answer: Option DExplanation:
To earn Rs. 10, money invested = Rs. 100.
To earn Rs. 12, money invested = Rs.100x 12= Rs. 120.
10 Market value of Rs. 100 stock = Rs. 120

7 A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is:

A.5.15 kmph
B.4.14 kmph
C.4.25 kmph
D4.4 kmph
Answer: Option BExplanation:

8 100 oranges are bought at the rate of Rs. 350 and sold at the rate of Rs. 48 per dozen. The percentage of profit or loss is:

9 What was the day of the week on 28th May, 2006?
A.Thursday
B.Friday
C.Saturday
D.Sunday
Answer: Option DExplanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.Given day is Sunday.

10 The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:

A.279
B.283
C.308
D.318
Answer: Option C
Other number =11 x 7700 = 308.275

11 How many digits will be there to the right of the decimal point in the product of 95.75 and .02554 ?

A.5
B.6
C.7
D.None of these
Answer: Option BExplanation:
Sum of decimal places = 7.
Since the last digit to the extreme right will be zero (since 5 x 4 = 20), so there will be 6 significant digits to the right of the decimal point.

12 One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in:
A.81 min.
B.108 min.
C.144 min.
D.192 min.
Answer: Option CExplanation:
Let the slower pipe alone fill the tank in x minutes.

13 A man purchased a cow for Rs. 3000 and sold it the same day for Rs. 3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, then the man has a gain of:
A 0%
B.5%
C.7.5%
D.10%
Answer: Option AExplanation:
C.P. = Rs. 3000.

S.P. = Rs.

3600 x 100

= Rs. 3000.
100 + (10 x 2)
Gain = 0%.

14 Find out the wrong number in the series.

6, 12, 48, 100, 384, 768, 3072

A.768
B.384
C.100
D.48
E.12
Answer: Option CExplanation:
Each even term of the series is obtained by multiplying the previous term by 2.
2nd term = (1st term) x 2 = 6 x 2 = 124th term = (3rd term) x 2 = 48 x 2 = 96.6th term = (5th term) x 2 = 384 x 2 =768. 4th term should be 96 instead of 100

15 David gets on the elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time, Albert gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross ?
A.19
B.28
C.30
D.37
Answer: Option C

Contact Details:
CISCO Systems Private Limited
Anath Rd,
Udyog Vihar IV,
Sector 18,
Gurgaon,
Haryana 122008
India

Map Location:
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  #3  
Old October 5th, 2015, 04:55 PM
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Default Re: CISCO previous year placement papers

Hi I need the sample placement paper for CISCO?
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  #4  
Old October 5th, 2015, 04:56 PM
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Default Re: CISCO previous year placement papers

As per your request, I am providing you the sample placement paper for CISCO

Latest CISCO Placement Paper :


Section D

1. a=2, b=3, c=6
Find the value of c/(a+b)-(a+b)/c


2. What does the hexanumber E78 in radix 7.

(a) 12455
(b) 14153
(c) 14256
(d) 13541
(e) 131112

Ans. (d)


3. 10 : 4 seconds :: ? : 6 minutes

Ans. 900


4. Q is not equal to zero and k = (Q x n - s)/2.What is n?

(a) (2 x k + s)/Q
(b) (2 x s x k)/Q
(c) (2 x k - s)/Q
(d) (2 x k + s x Q)/Q
(e) (k + s)/Q


5. From the following statements determing the order of ranking M has double the amount as D Y has 3 rupess more than half the amount of D

Ans. Data insuffiecient


Questions 6 - 10 are to be answered on the following data
A causes B or C, but not both
F occurs only if B occurs
D occurs if B or C occurs
E occurs only if C occurs
J occurs only if E or F occurs
D causes G,H or both
H occurs if E occurs
G occurs if F occurs

6. If A occurs which of the following must occurs

I. F and G
II. E and H
III. D

(a) I only
(b) II only
(c) III only
(d) I,II, & III
(e) I & II (or) II & III but not both

Ans. (e)


7. If B occurs which must occur

(a) D
(b) D and G
(c) G and H
(d) F and G
(e) J

Ans. (a)


8. If J occurs which must have occured

(a) E
(b) either B or C
(c) both E & F
(d) B
(e) both B & C

Ans. (b)


9. Which may occurs as a result of cause not mentioned

I. D
II. A
III. F

(a) I only
(b) II only
(c) I & II
(d) II & III
(e) I,II & III

Ans. (c)

10. E occurs which one cannot occurs

(a) A
(b) F
(c) D
(d) C
(e) J

Ans. (b)


Sample placement paper for CISCO
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Old November 4th, 2015, 02:46 PM
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Default Re: CISCO previous year placement papers

Hey buddy can you please get the CISCO exam placement paper so that I can also go through it.
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Old November 4th, 2015, 02:47 PM
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Default Re: CISCO previous year placement papers

As per your demand I will help you here to get the CISCO exam placement paper so that you can also solve it and get selected in to this.

Here is the CISCO exam placement paper


The starting location of an array is 1000. If the array[1..5/...4] is stored in row major order, what is the location of element[4][3]. Each work occupies 4 bytes.

If the number of leaves in a binary tree are N, then the total number of internal nodes........(Assume complete binary tree)
ANS: N-1
The locality of reference means.............

If two ausigned 8 bit numbers are multiplied what is the memory space required...............
The vector address of RST 7.5 is ............
ANS: 003C (multiply 7.5 by 8 and convert to hex



int b = 0xAA;
b>>4;
printf("%x",b);
What is the output of the above program....



1. struct s1 { struct { struct {int x;}s2}s3}y;
How to access x? ANS: y.s3.s2.x



2. Why there is no recursion in Fortran?
ANS: There is no dynamic allocation


3. What is the worst case complexity of Quick sort?
ANS: O(n^2)


4. Quick sort uses..............
Ans: Divide and conquer


5. In a sequential search, the time it takes to search through n elements is



6. What is the size of the array declared as double * X[5]
ANS: 5* sizeof (double *)



7. A binary search tree is given and asked to write the preorder traversal result.


8. If size of the physical memory is 2^32-1, then the size of virtual memory......


9. S-> A0B
A-> BB|0
B-> AA|1 How many strings of length 5 are possible with the above productions??


10. (3*4096+15*256+3*16+3). How many 1's are there in the binary representation of the result.
ANS: 10


11. In memory mapped I/O how I/O is accessed.............
ANS: Just like a memory location (Means, I/O devices can be accessed using the instructions like mov A,M etc...)


12. What is the use of ALE in 8085.......
ANS: To latch the lower byte of the address.


13. If the logical memory of 8 X 1024 is mapped into 32 frames, then the number of bits for the logical address ......
ANS: 13


14. Context free grammar is useful for...
ANS: If-then structures.


15. In ternary number representation, numbers are represented as 0,1,-1. Here -1 is represented as - (1 bar). Then how is 352/9 represented......



16. There are processors which take 4,1,8,1 machine cycles respectively. If these are executed in round robin fashion with a time quantum of 4, what is the time it take for process 4 to complete....

ANS: 9


17. The minimum frequency of operation is specified for every processor because......



18. In memory mapped I/O, what will happen if a device is identified with a 16 bit address and enabled by memory related control signals.....



19. The reason for preferring CMOS over NMOS is....
Ans: Low power consumption.


20. Two binary numbers A,B are given and asked to find out A-B.



21. Each character is represented by 7 bits, 1 bit is used to represent error bit and another bit for parity. If total number of bits transmitted is 1200bits, then number of symbols that can be transmitted.......


22. One question about the setassociativity of cache..


23. Write the postfix form of the following expression...
A+[[(B+C)+(D+E)*F]/G]


24. What is the function of the linker......


25. void f(int y)
{
struct s *ptr;
ptr = malloc (sizeof (struct)+ 99*sizeof(int));
}

struct s{
int i;
float p;
};
when free(ptr) is executed, then what will happen??


system concepts:

1. int a[5,6]
how much memory will be allocated

2. char p[6];
char *d[10];
ans:d=(char*)p

3. using LFU algorithm,how many page faults will occur of the pages r
1,2,1,3,4.
ans:1,4

4. in which layer the bridges r used.
a)data link layer
b)session layer
c)physical layer
d)network layer


5. #define d 10+10
main()
{ printf("%d",d*d);
}

6. in a complete binary tree if the number of levels r 4 then the number of
nodes will be,

7. if we delete a node from a balanced binary tree,how can we retain the
properties of balanced binary tree.
ans: by rotation at the nodes.

8. in a k-way search tree with N keys, the number of node/no. of leaves=

9. s->A0B
A->BB|1
B->AA|0
how many string can be constructed with length 5.

10. in which of the following regular expression the srting contains
atleast 2 concetive 1's.
ans0+10)*||(0+1)*

11. int i,j=1;
for(i=0;i<10;i++);
{
j=j+1;
}
printf("%d %d",i,j);

ans:10 11



12. static char *i;
i=malloc(sizeof(char));
find the error;
ans:malloc returns void



13. virtual memory address capacity depends on--



14. main()
{ int i=1;
fork();
fork();
fork();
printf("%d",i);
}
how many times i will be printed
ans:8


15. question on threads


16. int i=0xaa
char *p;
p=(char *)i;
p=p>>4;
printf("%x",p);
ans:0x000000a;

17. union
{ char *p;
int i;
char b;
}
main()
{
--
p=(char*)malloc(8*sizeof(char));
}
what is the size of union?

18. enum{sunday=-1,monday,...saturday}
printf("%d %d",sizeof(wednesday),wednesday);

19. struct x{
struct{
struct{
char ch;
} x;
}};
ans:definition wrong

20. struct *s;
s=(struct *)malloc(10*sizeof(struct)+90*sizeof(int));
free(s);
ans:total memory deallocated

21. one alogrithm is given:
ans:10395

22. func()
{ int x=1;
if(x=1)
x=1000;
else
x=10;

return x;
}
what is the return value?
ans:1000
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