IIT-JEE Previous year Papers

Will you please provide me question paper for IIT JEE examination ??

Here I am giving you question paper for IIT JEE examination in PDF file attached with it so you can get it easily..

A. Question paper format:
1. The question paper consists of 3 parts (Chemistry, Mathematics and Physics). Each part has 4 sections.
2. Section I contains 8 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for its
answer, out of which only one is correct.
3. Section II contains 4 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for its
answer, out of which one or more is/are correct.
4. Section III contains 2 groups of questions. Each group has 3 questions based on a paragraph. Each question
has 4 choices (A), (B), (C) and (D) for its answer, out of which only one is correct.
5. Section IV contains 2 questions. Each question has four statements (A, B, C and D) given in column I and five
statements (p, q, r, s and t) in Column II. Any given statement in column I can have correct matching with one
or more statements(s) given in column II. For example, if for a given question, statement B matches with the
statements given in q and r, then for that particular question, against statement B, darken the bubbles
corresponding to q and r in the ORS.
B. Marking scheme:
6. For each question in Section I you will be awarded 3 marks if you darken the bubble corresponding to the
correct answer and zero mark if no bubble is darkened. In case of bubbling of incorrect answer, minus one
(-1) mark will be awarded.
7. For each question in Section II, you will be awarded 4 marks if you darken the bubble(s) corresponding to
the correct choice(s) for the answer, and zero mark if no bubble is darkened. In all other cases, Minus one
(-1) mark will be awarded.
8. For each question in Section III, you will be awarded 4 marks if you darken the bubble(s) corresponding to
the correct answer and zero mark if no bubble is darkened. In all other cases, minus one (-1) mark will be
awarded.
9. For each question in Section IV, you will be awarded 2 marks for each row in which you have darkened the
bubble(s) corresponding to the correct answer. Thus, each question in this section carries a maximum of 8
marks. There is no negative marking for incorrect answer(s) for this section

IITJEE 2009 (PAPER-1, CODE-1)
SECTION-I
Single Correct Choice Type
This section contains 8 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for its answer,
out which ONLY ONE is correct.
1.
The Henry’s law constant for the solubility of N2 gas in water at 298 K is 1.0 × 105 atm. The mole fraction
of N2 in air is 0.8. The number of moles of N2 from air dissolved in 10 moles of water at 298 K and 5 atm
pressure is
(A) 4.0 × 10-4
(B) 4.0 × 10-5
(C) 5.0 × 10-4
(D) 4.0 × 10-6
Sol.
(A)
P = KH
2
N
χ
0.8 × 5 = 1 × 105 ×
2
N
χ
2
N
χ = 4 × 10-5
(in 10 moles of water)
2
2
N
5
N
n
4 10
n
10
-
⇒ ×
=
+
2
2
5
4
N
N
n
5 10
4 10
n
-
-
× ×
+ ×
=
2
4
N
n
4 10-
⇒
= ×
2.
The correct acidity order of the following is
OH
OH
Cl
COOH
COOH
CH3
(I)
(II)
(III)
(IV)
(A) (III) > (IV) > (II) > (I)
(B) (IV) > (III) > (I) > (II)
(C) (III) > (II) > (I) > (IV)
(D) (II) > (III) > (IV) > (I)
Sol.
(A)
OH
(I)
pKa = 9.98
OH
Cl
(II)
pKa = 9.38
COOH
(III)
pKa = 4.17
COOH
CH3
(IV)
pKa = 4.37
Decreasing order of acidic strength: III > IV > II >

3.
The reaction of P4 with X leads selectively to P4O6. The X is
(A) Dry O2
(B) A mixture of O2 and N2
(C) Moist O2
(D) O2 in the presence of aqueous NaOH
Sol.
(B)
P4 + 3O2
2
N
--→ P4O6 (exclusively)
(N2 is used to retard the further oxidation.)
4.
Among cellulose, poly(vinyl chloride), nylon and natural rubber, the polymer in which the intermolecular
force of attraction is weakest is
(A) Nylon
(B) Poly(vinyl chloride)
(C) Cellulose
(D) Natural Rubber
Sol.
(D)
As chain of natural rubber involves weak van der Waal force of interaction.
5.
Given that the abundances of isotopes 54Fe, 56Fe and 57Fe are 5%, 90% and 5% respectively, the atomic
mass of Fe is
(A) 55.85
(B) 55.95
(C) 55.75
(D) 56.05
Sol.
(B)
i i
i
A x
A
x
=
∑
∑
A
-
= 54 × 0.05 + 56 × 0.90 + 57 × 0.05 (where A
-
is atomic mass of Fe)
A
-
= 55.95
6.
The IUPAC name of the following compound is
OH
CN
Br
(A) 4-Bromo-3-cyanophenol
(B) 2-Bromo-5-hydroxybenzonitrile
(C) 2-Cyano-4-hydroxybromobenzene
(D) 6-Bromo-3-hdyroxybenzonitrile
Sol.
(B)
Priority of CN is highest.
7.
Among the electrolytes Na2SO4, CaCl2, Al2(SO4)3 and NH4Cl, the most effective coagulating agent for
Sb2S3 sol is
(A) Na2SO4
(B) CaCl2
(C) Al2(SO4)3
(D) NH4Cl
Sol.
(C)
As Sb2S3 is a negative sol, so, Al2(SO4)3 will be the most effective coagulant due to higher charge density
on Al3+ in accordance with Hardy-Schulze rule.
Order of effectiveness of cations: Al3+ > Ca++ > Na+ >

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Answered By StudyChaCha Member