BHEL Entrance Exam Paper Pattern

What is the pattern for Bharat Heavy Electricals Limited Entrance Exam Paper?

Bharat Heavy Electricals Limited (BHEL) is an Indian integrated power plant equipment manufacturer and operates as an engineering and manufacturing company based in New Delhi, India.

paper pattern for BHEL entrance exams

There are 240 questions in the paper and out of 240 120 are Technical and other 120 are Aptitude & General English questions.

There is a negative marking of 1/5th mark for each wrong answer

You should complete the paper within 150 minutes.

Important Date:

Starting Date for Online Registration (GATE 2013): 01/09/2012

Last Date for Online Registration (GATE 2013): 30/09/2012

Opening Date for BHEL Recruitment Website: 14/09/2012

Commencement of Submission of Online Application: January 2013

Date of GATE Exam for Mechanical, Electrical and Electronics: 10/02/2013

For paper visit here:-

http://studychacha.com/discuss/27580...ectronics.html

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I want to start preparation for BHEL Entrance Exam . will you please give here BHEL exam paper pattern as I am looking for the same?

As you want I am here giving you BHEL entrance exam pattern.

BHEL entrance exam pattern :

Objective type test .

Multiple choice questions on the following:

General Aptitude: 30 Questions

Comprehension/ Passage based questions: 3 Questions

Data Interpretation
Logical Reasoning
General Knowledge questions

Technical Questions from the subject chosen by the candidates.

Sample paper :
1)A train covers a distance in 50 min ,if it runs at a speed
of 48kmph on an average.The speed at which the train must run
to reduce the time of journey to 40min will be.
1. Solution::
Time=50/60 hr=5/6hr
Speed=48mph
distance=S*T=48*5/6=40km
time=40/60hr=2/3hr
New speed = 40* 3/2 kmph= 60kmph
2)Vikas can cover a distance in 1hr 24min by covering 2/3 of
the distance at 4 kmph and the rest at 5kmph.the total
distance is?

Let total distance be S
total time=1hr24min
A to T :: speed=4kmph
diistance=2/3S
T to S :: speed=5km
distance=1-2/3S=1/3S
21/15 hr=2/3 S/4 + 1/3s /5
84=14/3S*3
S=84*3/14*3
= 6km
3)walking at ¾ of his usual speed ,a man is late by 2 ½ hr.
the usual time is.

3. Solution::
Usual speed = S
Usual time = T
Distance = D
New Speed is ¾ S
New time is 4/3 T
4/3 T – T = 5/2
T=15/2 = 7 ½

4)A man covers a distance on scooter .had he moved 3kmph
faster he would have taken 40 min less. If he had moved
2kmph slower he would have taken 40min more.the distance is.

4.Solution::
Let distance = x m
Usual rate = y kmph
x/y – x/y+3 = 40/60 hr
2y(y+3) = 9x ————–1
x/y-2 – x/y = 40/60 hr y(y-2) = 3x —————–2
divide 1 & 2 equations
by solving we get x = 40

Here is the attachment.

Attached Files Available for Download

BHEL entrance exam paper.pdf (195.3 KB, 23 views)

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