JEE Advanced Official Cut off Marks

Hi I am interested in having the information about JEE Advanced Cut-off 2017 and also Minimum percentage of marks for inclusion in a rank list?

JEE Advanced Cut-off 2017 is the base denote that an applicant needs to secure to be qualified for getting admission to undergrad designing projects offered crosswise over Indian Institutes of Technology (IITs) and Indian School of Mining (ISM) Dhanbad. IIT Madras, the arranging organization for JEE Advanced 2017, will declare the total and segment insightful least stamps endorsed for consideration in the rank rundown.

JEE Advanced Cut-off 2017:

Just those hopefuls will be considered for affirmations crosswise over JEE Advanced 2017 Participating Institutes who will score over the predetermined cut-off. JEE Advanced 2017 Cut-off will be chosen the premise of various components like aggregate number of accessible seats and qualified hopefuls, and so forth.

Maximum marks required for qualifying JEE Advanced 2016

S.No.
Aggregate/Subject
Maximum Marks Required

1.
Maximum aggregate marks
372 (186 each in Paper-1 and Paper-2)

2.
Maximum marks in Physics
124 (62 each in Paper-1 and Paper-2)

3.
Maximum marks in Chemistry
124 (62 each in Paper-1 and Paper-2)

4.
Maximum marks in Mathematics
124 (62 each in Paper-1 and Paper-2)

Minimum percentage of marks for inclusion in a rank list is given blow:

Rank list
Minimum percentage of marks in each subject
Minimum percentage of aggregate marks

Common rank list
10.0
35.0

OBC-NCL rank list
9.0
31.5

SC rank list
5.0
17.5

ST rank list
5.0
17.5

OPEN-PwD rank list
5.0
17.5

OBC-NCL-PwD rank list
5.0
17.5

SC-PwD rank list
5.0
17.5

ST-PwD rank list
5.0
17.5

Preparatory course rank lists
2.5
8.75

Maximum aggregate marks: 264 (Paper-1) + 240 (Paper-2) = 504
Maximum marks in Physics: 88 (Paper-1) + 80 (Paper-2) = 168
Maximum marks in Chemistry: 88 (Paper-1) + 80 (Paper-2) = 168
Maximum marks in Mathematics: 88 (Paper-1) + 80 (Paper-2) = 168

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Answered By StudyChaCha Member