IIT JEE Mathematics Papers

I need the Indian Institute of Technology Joint Entrance Examination Mathematics papers so please can you provide me the papers and tell me from where I can download the papers free of cost?

As you are searching for the IIT JEE Maths paper to prepare for the exam. Here I am providing you PDF file link which contain question paper in which there are more than 56 questions.

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Here I am providing you the IIT Maths Sample Paper 2

The paper is as follows:

Algebra
1. Simplify the expression (a > 0, a ¹ 0) : (a-x/Ö 5)[2a2x-ax(2ax-1)] {1-(Ö5ax/2ax-1)-2}-1/2´ Ö[(ax+2)2-5]-(a2x+4)[a2x+4(1-ax)]-1/2+4ax[1+(ax+2)(a2x-4ax+4)-1/2]{ax+2+(a2x-4ax+4)1/2}-1 and determine for which values of x this expression is equal to 1.

2. Prove that log418 is an irrational number.

3. Determine all such integers a and b for which one of the roots of 3x3+ax2+bx+12=0 is equal to 1 + Ö3.

4. Solve in terms of complex numbers: z3 + (w7)*=0; z5.w11 = 1. (* indicates conjugate).

5. Prove that if a > 0, b > 0 then for any x and y the following inequality holds true: a.2x+b.3y+1 £ Ö(4x+9y+1)Ö(a2+b2+1)

6. Prove the inequality nn+1 > (n+1)n, n ³ 3, n Î N.

7. Prove that (b+c)2 a2 a2
b2 (c+a)2 b2
c2 c2 (a+b)2
= 2abc(a+b+c)3

(Without expanding)

8. Sum the series: 1 + 4x + 9x2 + ...

9. The eqns ax2 + bx + c=0 and x3=k have a common root. Prove that a b c
b c ak
c ak bk
= 0

10. If w is a root of x4=1 then Show that a + bw + cw2 + dw3 is a factor of a b c d
b c d a
c d a b
d a b c


Hence Show that the det is equal to -(a+b+c+d)(a-b+c-d){(a-c)2+(b-d)2}.

11. Find the coefficient of x4 in (1 + 2x + 3x2)5.

12. The sum of squares of 3 terms of a GP is S2. If their sum is aS, Prove that a2 Î (1/3,1) È (1,3).

13. Find the sum to n terms: 0!/5! + 1!/6! + 2!/7! + ...

14. If f(x)=ax/(ax + Öa) (a > 0), evaluate r=1å2n-1 f(r/2n).

This section contains 6 multiple choice questions. Each question has 4 choices (1), (2), (3) and (4), out of which ONLY ONE is correct.

1. If 0 < x < 1 then √1+x2 [{x cos (cot-1 x) + sin (cot-1 x)}2 - 1]1/2
(1) x/√1+x2
(2) x
(3) x√1+x2
(4) √1+x2

2. Consider the two curves
C1 : y2 = 4x
C2 : x2 + y2 - 6x + 1 = 0
Then,
(1) C1 and C2 touch each other only at one point
(2) C1 and C2 touch each other exactly at two points
(3) C1 and C2 intersect (but do not touch) at exactly two points
(4) C1 and C2 neither intersect nor touch each other

3. The edges of a parallelopiped are of unit length and are parallel to non-coplanar unit vectors a, b, c such that a.b = b.c = c.a = 1/2
Then, the volume of the parallelopiped is
(1) 1/√2
(2) 1/2√2
(3) √3 / 2
(4) 1/√3

4. Let a and b be non-zero real numbers. Then, the equation (ax2 + by2 + c) (x2 - 5xy + 6y2) = 0 represents
(1) four straight lines, when c = 0 and a, b are of the same sign
(2) two straight lines and a circle, when a = b, and c is of sign opposite to that of a
(3) two straight lines and a hyperbola, when a and b are of the same sign and c is of sign opposite to that of a
(4) a circle and an ellipse, when a and b are of the same sign and c is of sign opposite to that of a.

Here I m giving you the attachment PDF file for IIT JEE Paper. You can download free from here.

Attached Files Available for Download

IIT JEE Papers.pdf (303.2 KB, 21 views)

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Answered By StudyChaCha Member

Hey can you provide me IIT JEE Mathematics Papers.

The Indian Institute of Technology takes an annual entrance exam known as IIT-JEE.

Syllabus:-
The Mathematics papers comprise of syllabus that extend from that of Class 12 and Class 11.

I have attached PDF file that have Mathematics Papers for IIT JEE.

1. For a first order reaction A → P, the temperature (T) dependent rate constant (k) was found to follow the
equation log k = –(2000) 1 6.0
T
+ . The pre-exponential factor A and the activation energy Ea, respectively,
are
(A) 1.0 × 106s–1 and 9.2 kJ mol–1 (B) 6.0 s–1 and 16.6 kJ mol–1
(C) 1.0 × 106 s–1 and 16.6 kJ mol–1 (D) 1.0 × 106 s–1 and 38.3 kJ mol–1
Key. (D)
Sol. Ea/RT k Ae− =
a E
log k logA
2.303RT
= −
Log A = 6, A = 106s–1
a E 2000
2.303 8.3 T T
− = −
× ×
Ea = 2000 × 2.303 × 8.3 J
= 38.3 kJ

2. The spin only magnetic moment value (in Bohr magneton units) of Cr(CO)6 is
(A) 0 (B) 2.84
(C) 4.90 (D) 5.92
Key. (A)
Sol. Cr(CO)6
Cr(zero)
Atomic configuration : 1s2 2s2 2p6 3s2 3p6 4s1 3d5
CO is a strong field ligand
∴ Configuration 2g t
No. of unpaired electron = 0
∴ magnetic moment =

Attached Files Available for Download

IIT JEE Mathematics Papers.pdf (1.88 MB, 24 views)

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