Syntel Online Placement Papers with Answers

Hello, I am applying for the Syntel of campus placements and I want the papers of the previous years for the reference.

Hello, here I am providing you some of the sample questions of the Syntel placements as under:

Puzzle: There r 6 teachers ABCDE & a&b is teaching history &english b&c is
teaching maths&hindi & so on...................
Q: How many teachers r teaching maths?
Q: How many r taking more than 2 subjects? etc (Easy but concentrate with time
management )

1. A family I know has several children. Each boy in this family has as many sisters as brothers but each girl has twice as many brothers as sisters. How many brothers and sisters are there?

Ans: 4 boys and 3 girls.

2. In a soap company a soap is manufactured with 11 parts. For making one soap you will get 1 part as scrap. At the end of the day u have 251 such scraps. From that how many soaps can be manufactured?

Ans: 25.

3. There is a 5digit no. 3 pairs of sum is eleven each. Last digit is 3 times the first one. 3 rd digit is 3 less than the second.4 th digit is 4 more than the second one. Find the digit.

Ans : 25296.

4. Every day a cyclist meets a train at a particular crossing. The road is straight before the crossing and both are traveling in the same direction. The cyclist travels with a speed of 10 Kmph. One day the cyclist comes late by 25 min. and meets the train 5km before the crossing. What is the speed of the train?

Ans: 60 kmph

5. Two twins have certain peculiar characteristics. One of them always lies on Monday, Wednesday, and Friday. The other always lies on Tuesdays, Thursdays and Saturdays. On the other days they tell the truth. You are given a conversation.

Person A-- today is Sunday my name is Anil
Person B -- today is Tuesday, my name is Bill
What day is today?

Ans: Today is Tuesday

Directions 6:10

In each of the questions given below which one of the five answer figures on the right should come after the problem figures on the left, if the sequence were continued ?
Answers 6-10

6 E. 7. C 8. B 9.E 10. D

Directions 11-15: Each problem consists of a problem followed by two statements. Decide whether the data in the statements are sufficient to answer the question. Select your answer according to whether:
(A) statement 1 alone is sufficient, but statement 2 alone is not sufficient to answer the question
(B) statement 2 alone is sufficient, but statement 1 alone is not sufficient to answer the question
(C) both statements taken together are sufficient to answer the question, but neither statement alone is sufficient
(D) each statement alone is sufficient
(E) statements 1 and 2 together are not sufficient, and additional data is needed to answer the question

11. If x and y are both positive integers, how much greater is x than y?
x + y = 20
Syntel Placement Question Papers
1:Written test paper with eassy writting
2:HR(elimination round)
3:Technical inter.
Written::50 questions for 45 minutes
Q1 to Q5 Analogy
Eg 1Hourse:Mare::Husband:?
options:: wife,daughter.......etc
2 ) Doct.:treatment::advocate:? Like this
further they have given some jumbled letters and we have to put that into a
correct sequence
Eg: KAAABHSR =43335126
options: 12345633
54321633
51324363(Correct option)=(Ans BHASKARA)
Next 5 questions : a puzzle was given :
Puzzle: There r 6 teachers ABCDE & a&b is teaching history &english b&c is
teaching maths&hindi & so on...................
Q: How many teachers r teaching maths?
Q: How many r taking more than 2 subjects? etc (Easy but concentrate with time
management )
Next 5 questions were from aptitude:
Time &Work(Go through R.S Agarwal) easy but Logic must me clear to U
Next 10 Q were the tabulation Problem similar to one given in the R.S Agarwal(Go
through it)
Now VERBAL PART (15 QUESTIONS)
Fill in the blanks(3-4Q)
Fill with appropriate articles.
Vocab: a word was given & we have to choose from the given options its opposite
or its related meaning(Little vocab Power required)
After this 10 minutes were given to us for eassy writting.
TIME MANAGEMENT REQUIRED
Results were announced after 6 hrs & out of 1300 students 200 students were
shortlisted for HR round
HR:
Advice ::Go through all the core questn.
q asked to me:
SHE: Speak about UR self for 1 min.
She: Tell me UR biggest strength U feel proud with
I: told
She: Biggest weakness
I: told
she :told me to discuss the topic given for eassy
She: Asked for queries

here I am providing you the files of sample papers as under:

Attached Files Available for Download

Syntel Online Placement Papers with Answers.pdf (13.5 KB, 21 views)

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I want to get a sample Placement Papers of Syntel for get job. So here can you provide me a sample paper of Syntel?

I have a sample paper of Syntel. So here I am providing you as you want.



A man goes 50Km north , then turned left walked 40Km, then turned right ? In which direction he is?
a) North b) South c) East d) West

The age of the two friends were in the ration of 6:5. If the sum of their ages is 66. Then after how many years their ratio will become 7:6?
a) 11 b) 6 c) 10 d) 12

A person has to make 146 pieces of a long bar. He takes 4 seconds to cut a piece. What is the total time taken by him in seconds to make 146 pieces?
a) 584 b) 580 c) 730 d) 725

Find the H.C.F. of 2/3, 3/9, 16/81 and 10/27.
a) 2/81
b) 80/3
c) 2/67
d) 3/19

The least number of 4 digits which is perfect square is:
a) 1100
b) 1200
c) 1024
d) None



Some of the questions

1. DIAMONDS : NECKLACE
2. TITAN : GIANT
3. SQUARE : CUBE
4. CENTURY : SCORE

Choose one word:
One who assails traditional beliefs:
a.) critic
b.) atheist
c.) anthropologist
d.) iconoclast

All of you will agree with me (1)/ that no problem faced by our (2)/ society is as grave and intractable (3)/ as this problem is. (4)/ No error(5)


Database Interview Questions -

1.What are logical operators?

2. What is the actual value of NULL?

3. What do you understand by column aliases?

4. What is the purpose of column aliases?

5. What are the different types of aliases present?

6. Is it necessary to close the statements with a semicolon (?

7. What is the difference between ROWCOUNT and WHERE clause?




Question:1

The straight distance between two places P and Q is 3000 meters. A boy moves with his cycle at a rate of 6/11 km/hr and he starts at 12.00 am from P to Q. Another boy moves with his cycle at a rate of 15/22 km/hr and he starts at 1.00 pm from Q to P. Then at what time they do meet?

a)1.30pm b)2pm c)3.30pm D)4pm

Answer: c)3pm

Solution:

Given that the distance between two places P and Q is 3000 meters = 3km
Suppose two boys meet X hours after 12.00 am
Distance covered by the 1st boy in X hours at 6/11 km/hr = time x speed = X x 6/11 = 6X/11 km
2nd boys starts 1 hour later than the 1st one.
Then the distance covered by 2nd boy in (X-1) hours at 15/22 km/hr = 15(X-1)/22 km
Now, total distance between A and Q = 3km
This means, at the meeting instance the sum of the distances covered by both the boys should be 3 Km
i.e., 6X/11 + 15(X-1)/22 = 3
=> 12X+15X-15 / 22 = 3
=> 27X-15 / 22 = 3
=> 27X-15 = 66
=> 27X = 66+15 = 81
=> X = 81/27 = 3
Thereore, they meet 3 hours after 12.00am
Hence the answer is 3 pm.

Question:2

Let X and Y be two ends of a long road of length 2 km. If Jo and her sister start at the same time from X and Y respectively and if they run in opposite directions they meet after 10 minutes. Instead of running in opposite direction, in case if they had started running in same direction Jo would have met her sister after 30 minutes. Then the speed of Jo is:

a)4km/hr b)10km/hr c)8km/hr d)3km/hr

Answer: c)8km/hr

Solution:

Case I. Running in opposite direction (towards each other) :

At the meeting point i.e after 10 minutes since start, the distance covered by Jo from X + distance convered by Sister from Y should be equal to the distance between X and Y, which is 2 km.

i.e Distance covered by Jo from X to the meeting point + Distance covered by Sister from Y to the meeting point = 2 ...(1)

Distance covered by Jo from X to the meeting point = Speed x Time = P km/hr x 10 minutes = P km/hr x (1/6) hours = P/6 KM
Distance covered by Sister from Y to the meeting point = Speed x Time = Q km/hr x 10 minutes = Q km/hr x (1/6) hours = Q/6 KM

Therefore, eq (1) becomes

P/6 + Q/6 = 2
=>(P+Q)/6 = 2
=> P+Q = 12 ...(2)

Case II. Running in same direction :

Since it is given that Jo meets her sister after 30 minutes, we can safely be assured that Jo after starting from X has followed her sister who started from Y.

Relative speed of Jo with respect to her sister = Speed of Jo - Speed of Sister = P - Q

Since Jo has started 2 km behind his sister (remember that X which is the starting point of Jo is 2 km apart from Y which is the starting point of his sister), if the time taken for him to make up for this lag will be the actual meeting time.

This happens, when the relative speed of Jo with respect to sister is good enough to cover the distance of 2 km.

Time taken at the meeting point = Initial distance of separation / Relative speed of Jo with respect to sister = 2 Km / P - Q = 2/ P - Q

But this time is given to be 30 minutes or 1/2 hours.

i.e 2/ P - Q = 1/2

=> P - Q = 4 ...(3)

(2) + (3) gives,

2P = 16

Or P = 8 Km/hr

And P represents the speed of Jo. Hence our answer is 8 Km/hr

Question:3

A van starts from a station A at a speed of 45km/hr and travels towards another station Y. Another van starts at the same time as that of the first van from Y at a speed of 35km/hr and travels towards X. If 2nd van travelled 50km less than the 1st one when they meet then what will be the distance between two stations X and Y ?

a)400km b)200km c)250km d)350km

Answer: a)400km

Solution:

At the time of meeting, let the distance travelled by the 1st van be P km.
Then distance covered by second van P-50 km.
Time taken by 1st to cover P km at 45km/hr = P/45 ...(1)

Time taken by 2nd to cover P-50 km at 35km/hr = (P-50)/35 km ...(2)
Since both trains have started at the same time, during the time of crossing, each would have travelled for the same time duration

Therefore, we can equate the values of (1) and (2).
i.e P/45 = (P-50)/35
=> 35P = (P-50)45
=> 35P = 45P - 2250
=> 10P = 2250
=> P = 225 ...(3)

Distance between X and Y = distance covered by first Van during crossing + distance convered by second Van during crossing = P + P - 50 = 2P-50.
Substituting the value of P from eq (3) in above equation, we get,
Distance between X and Y = 2(225)-50 = 400km
Hence, the distance between two stations X and Y is 400km.

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