JNTU Kakinada BITS

Hello Sir I am a student of Jawaharlal Nehru Technological University Kakinada and I want to know about the JNTU BITS and provide me the all information about the JNTU Kankinda BITS?

From where I can downloads the Jawaharlal Nehru Technological University Kakinada 3-1 1st Mid Online Bits so please tell me that from where can I get this.

Here I am giving you questions of the Jawaharlal Nehru Technological University Kakinada 3-1 1st Mid Online Bits with answer as given below:-

1. Feature of OOPS is Used to define new data types
Ans-overload

2. C++ encourages structuring a software as a collection of component that are
Ans-highly cohesive and loosely coupled

3. A normal C++ operator that acts in a special ways on newly defined types is said to be
Ans- overloaded

If you want to see more question then download given below attachment:-

Attached Files Available for Download

JNTU Kakinada Question Bits.pdf (187.1 KB, 72 views)

__________________
Answered By StudyChaCha Member

Will you please provide the question paper of Digital Logic Design bits of 2-1 1st Mid Online of JNTU kakinada?

As you are looking for the question paper of Digital Logic Design bits of 2-1 1st Mid Online of JNTU kakinada , here i am providing list of few questions.
1) 1.The number of zero bits precede the binary number will = Ans:-does not change its
Value

2) Group of four bits are called Ans:-nibbles

3) Group of sixteen bits are called Ans:- words

4) The byte can represent signed numbers in the range of = Ans:--128 .....+127

5) Inside today's computers, data is represented as Ans:-zeros = and ones

6) Most modern digital systems operate using a Ans:-binary = logic

7) Binary uses a powers of Ans:-2

8) To convert a binary number to decimal Ans:- for each '1' in = the binary string, add 2n

9) The decimal equivalent of 0000000111 is Ans:-7

10) The left most bit is typically called the Ans:- higher order = bit

11) Group of eight bits are called Ans:-bytes

12) The smallest unit of information which a computer can understand = is Ans:- bit

13) Convert the binary number 11.11 in to the decimal = Ans:-3.75

14) ( 2AC5.D)16 =3D ( ? )8 Ans:-10949. 8125 =

15) (623.77)8 =3D ( ?)16 Ans:- 193.FC

16) Going form binary to hexadecimal, grouping of four bits can be = obtained by Ans:-
added as zero









Contact:
Jawaharlal Nehru Technological University
Main Road, Kukatpally Housing Board Colony, Kukatpally,Hyderabad, Andhra Pradesh, 500085 ‎
040 2315 8661

Map:

__________________
Answered By StudyChaCha Member