Shortcuts to Solve the Aptitude Questions - 2018-2019 StudyChaCha

#1
June 6th, 2014, 12:24 PM
 Unregistered Guest Posts: n/a
Shortcuts to Solve the Aptitude Questions

Can any buddy here please provide me some Short Tricks and Formula to solve Quantitative Aptitude Questions???
#2
June 6th, 2014, 05:01 PM
 Super Moderator Join Date: Jun 2011 Posts: 35,928
Re: Shortcuts to Solve the Aptitude Questions

Quantitative Aptitude is necessary for competitive exams. To succeed in the competitive exams what we need to have is Speed and Accuracy which can be achieved through shortcut techniques.

Let us consider some examples to learn Short Tricks and Formula to solve Quantitative Aptitude Question

Example 1
The age of a father 3 years ago was 7 times the age of his son. At present the age of son is five times the age of son. What are the present age of father and son ?

Solution:
Let the present age of son = x years
the present age of father = 5x years
3 years ago
sons age = x-3
Fathers age = 5x-3
7(x-3) = 5x-3
7x-21=5x-3
2x=18
x=9
So, Present age of son is 9 years and father is 5*9=45.

Shortcut---
Sons Age = T1(x-1)/x-y= 3*(7-1)/(7-5) = 9

Example 2
A sum of money doubles itself in 10years at S.I . What is the rate of Interest.
Solution:
Let the sum be x
After 10 years it becomes 2x
Interest= Rs.2x- Rs.x =Rs.x
Rate = 100*l/P*T =100*x/x*10 = 10%

Shortcut --
Time*Rate = 100(Multiple Number of Principal Amount -1)
Rate= 100 (Multiple Number of Principal Amount-1 ) /Time

Example
A sum of money doubles itself in 7 years.In how many years will it become four fold?

shortcut --
Double in 7 years
Triple in 14 years
4 times in 21 years
5 times in 28 years

Example
When a person covers a distance between his house and office at 50 km/hr . He is late by 20 min. But when he travels at 60km/hr. He reaches 10 min early.What is the difference between his house and office ?

Solution:
Let the distance be x km
Time taken to cover x km at 50km/hr is = x/50 hrs
Time taken to cover x km at 60km/hr is = x/60 hrs
Difference between time taken = 30 min
∴x/50-x/60 = 30/60
=> 6x-5x/300 = 1/2
=> x = 150 km

Shortcut --
Required Distance = Product of two speeds / Difference of two speeds * Difference between arrival time.

So Short cut should written after solving every type of problem in a separate notebook , and remember it well.
-This kind of shortcuts saves a lot of time while solving problems.
-By following shortcut methods one can solve problems in time with high degree of accuracy
__________________

#3
November 1st, 2015, 12:58 PM
 Unregistered Guest Posts: n/a
Re: Shortcuts to Solve the Aptitude Questions

Hello, I am preparing for various competition exams and I want to know the shortcuts to solve the aptitude questions.
#4
November 1st, 2015, 12:59 PM
 Super Moderator Join Date: Dec 2011 Posts: 14,245
Re: Shortcuts to Solve the Aptitude Questions

To succeed in the examinations, candidate should know the shortcut to solve the problem in a few seconds. Time management and accuracy are very important for solving the aptitude problems. Here I am providing you some tricks:
1. Work from Days:
If A can do a piece of work in n days, then A's 1 day's work = 1
.
n
2. Days from Work:
If A's 1 day's work =1
,then A can finish the work in n days.
n
3. Ratio:
If A is thrice as good a workman as B, then:
Ratio of work done by A and B = 3 : 1.
Ratio of times taken by A and B to finish a work = 1 : 3.
4. If A is 'x' times as good a workman as B, then he will take of the time by B to do
the same work.
5. A and B can do a piece of work in 'a' days and 'b' days respectively, then working
together, they will take days to finish the work and in one day, they will finish
part of work.

Solved questions:
1) Problem: If 9 men working 6 hours a day can do a work in 88 days. Then 6 men
working 8 hours a day can do it in how many days?
Solution: From the above formula i.e (m1*t1/w1) = (m2*t2/w2)
so (9*6*88/1) = (6*8*d/1)
on solving, d = 99 days.
2) Problem: If 34 men completed 2/5th of a work in 8 days working 9 hours a day.
How many more man should be engaged to finish the rest of the work in 6 days
working 9 hours a day?
Solution: From the above formula i.e (m1*t1/w1) = (m2*t2/w2)
so, (34*8*9/(2/5)) = (x*6*9/(3/5))
so, x = 136 men
number of men to be added to finish the work = 136-34 = 102 men
3) Problem: If 5 women or 8 girls can do a work in 84 days. In how many days can
10 women and 5 girls can do the same work?
Solution: Given that 5 women is equal to 8 girls to complete a work. So, 10 women =
16 girls. Therefore 10 women + 5 girls = 16 girls + 5 girls = 21 girls.
8 girls can do a work in 84 days then 21 girls can do a work in (8*84/21) = 32 days.
Therefore 10 women and 5 girls can a work in 32 days
4) Problem: Worker A takes 8 hours to do a job. Worker B takes 10 hours to do the
same job. How long it take both A & B, working together but independently, to do
the same job?
Solution: A's one hour work = 1/8. B's one hour work = 1/10. (A+B)'s one hour work
= 1/8+1/10 = 9/40. Both A & B can finish the work in 40/9 days
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