Infosys Solved Placement Papers - 2018-2019 StudyChaCha

#1
January 8th, 2014, 04:52 PM
 Unregistered Guest Posts: n/a
Infosys Solved Placement Papers

I am going to participate in Infosys exam, so need placement exam previous question paper, will you please provide here?
#2
January 9th, 2014, 11:26 AM
 Super Moderator Join Date: Jun 2013 Posts: 42,987
Re: Infosys Solved Placement Papers

Here are the Infosys placement exam solved questions:

Q15 marks)
a wall clock looses 10 mins in 1 hr. 4 one hours of wall clock table clock gains 10mins for 1 hour of
table clock alarm clock looses 5 mins for 1hr of aramm clock, wrist watch gains 5min
they were set correctly at 4 pm
what was the time of wrist watch at 6 pm(of correct time clock)

Q2:3 marks
Mr. Jonh was a inspector of falt finding in balancing sscal. He found that 1arm was longer than the
other one. When 8 pyramids were kept in the longer the cubes required were in the short arm.
When 1 pyramid is kept on longer arm the cubes required at shorts arm was 6.
if the correct weight of pyramid is 1 ounce.? Is the true weight of one cube.

Q3:6marks
They were 2 twins one of them say nothing but lies on Monday, Wednesday and Friday and truth on
other days. 2nd one says nothing but lies on Tuesday, Thursday, and Saturday. Only on sun both
speak truth.

Q4: (5 marks)
3 (A, B, C) players along with their wife (D, E, F) play a golf game, who scores less will win. Altogether
there were 18 games. C score 100, D - 102, E – 106. 94 was the score of B. 2 other man A, B scores
98 and 96. B's wife beats A's wife. It was found that 2 pair score identical then identify the pairs.

For detailed paper here is attachment:
Attached Files
 Infosys Placement Solved Paper.zip (222.3 KB, 174 views)
__________________

#3
January 9th, 2014, 12:15 PM
 Junior Member Join Date: Oct 2013 Posts: 10
Re: Infosys Solved Placement Papers

Hi , For any company placement exam you should focus on your syllabus content that you have been studied during your course. Check out all the fundamental concepts of important subjects.
#4
May 16th, 2014, 03:00 PM
 Unregistered Guest Posts: n/a
Infosys Solved Placement Papers

Please provide the previous year solved placement papers of Infosys?
#5
May 17th, 2014, 03:27 PM
 Super Moderator Join Date: Jun 2011 Posts: 35,928
Re: Infosys Solved Placement Papers

Infosys is a Multinational Company that deals in Information and technology, outsourcing and many more. The company recruits in a huge number for the various posts in its firms.

Sample Questions:

1) If x and y are the two digits f the number 653xy such that this number is divisible by 80, then x+y is equal to:

(i) 2
(ii) 3
(iii) 4
(iv) 6

Since 653xy is divisible by 2 as well as by 5, so y = 0
Now 653x0 is divisible by 8 so 3x0 is also divisible by 8.
By hit and trial x=6 and x+y = 6

2) The smallest number which when diminished by 3 is divisible by 21,28,36 and 45 is...

(i) 869
(ii) 859
(iii) 4320
(iv) 427

Answer is The required number = l.c.m. of (21,28,36 ,45)+3=1263

3) If 1.5x=0.04y then the value of (y-x)/(y+x) is

(i) 730/77
(ii) 73/77
(iii) 7.3/77
(iv) None
Answer is: x/y = 0.04/1.5 = 2/75
So (y-x)/(y+x) = (1 - x/y)/(1 + x/y) = (1 - 2/75)/ (1 + 2/75) = 73/77

4) The average age of a class is 15.8 years. The average age of boys in the class is 16.4 years while that of girls is 15.4 years. What is the ratio of boys to girls in the class?

(i) 1:2
(ii) 3:4
(iii) 3:5
(iv) None of these

Let the ratio be k:1.
Then k*16.4+1*15.4 + (k+1)*15.8 (16.4-15.8)k = 15.8 - 15.4 k=0.4/0.6 = 2/3 so required ratio = 2:3

1. A boy asks his father, “what is the age of grandfather?". Father replied " He is x years old in x^2 years", and also said, "we are talking about 20th century". What is the year of birth of grandfather?

Ans: 1892

2. A boy travels in a scooter after covering 2/3rd of the distance the wheel got punctured he covered the remaining distance by walk. Walking time is twice that of the time the boy’s riding time. How many times the riding speed as that of the walking speed?

Ans: 4 times.

3. In a Knockout tournament 51 teams are participated, every team thrown out of the tournament if they lost twice. How many matches to be held to choose the winner?

Ans: 101 matches

4. A man sold 2 pens. Initial cost of each pen was Rs. 12. If he sell it together one at 25% profit and another 20% loss. Find the amount of loss or gain, if he sells them separately.

Ans: 60 Paise gain

5. The Novice hockey tournaments are on for beginners. Just three teams are in the league, and each plays the other two teams just once. Only part of the information appears in the result chart, which is given below.

Team

Games

Won

Lost

Tied

Goals For

Goals against

The scoring pattern in the tournament is as follows:

Two points are awarded to the winning team. In case of a tie, both teams are awarded one point, so the total points in the standings should always equal the total number of games played (since each game played is counted as one for each of the two participating teams). Of course, total goals scored for and goals scored against must be the same, since every goal scored for one team is scored against another.

The games are played in the following order: Game 1: A Vs B; Game 2: A Vs C; Game B Vs C
Can you determine the score of each of the above games ?

Ans: A – B = 0-1.
A – C = 0-0.
B – C = 0-2.

6. A recent murder case centered around the six men, clam, flip, gront, herm, mast, and walt. In one order or another man were the victim, the murderer, the witness, the police, the judge, and the hangman. The facts of the case were simple. The victim had died instantly from the effect of gunshot wound inflicted a shot. After a lengthy trial the murderer was convicted, sentenced to death, and hanged.

Mast knew both the victim and the murderer.
In court the judge asked clam his account of the shooting.
Walt was the last of the six to see flip alive.
The police testified that he picked up gront near the place where the body was found.
Herm and Walt never met.

What role did each of the following play in this melodrama?

Murderer – Flip
Victim - Herm
Judge - Mast
Witness - Gront

7. Jim, Bud and Sam were rounded up by the police yesterday because one of them as suspected of having robbed the local bank. The three suspects made the following statements under intensive questioning.

Jim: I'm innocent
Bud: I'm innocent
Sam: Bud is the guilty one.

If only one of the statements turned out to be true, who robbed the bank?

Ans: BUD.

8. There are two containers on a table. A and B. A is half full of wine, while B, which is twice A's size, is one quarter full of wine. Both containers are filled with water and the contents are poured into a third container C. What portion of container C's mixture is wine?

Ans: 33.33%

Here I am attaching the Solved Placement papers of Infosys:
Attached Files
 Infosys placement paper.pdf (80.8 KB, 65 views)
__________________
#6
October 17th, 2015, 11:41 AM
 Unregistered Guest Posts: n/a
Re: Infosys Solved Placement Papers

hii sir, I wanted to join the Infosys therefore please provide me the sample paper of the Aptitude test ?
#7
October 17th, 2015, 11:44 AM
 Super Moderator Join Date: Jun 2013 Posts: 42,294
Re: Infosys Solved Placement Papers

As you asking for the Sample paper of the Aptitude test of the Infosys ,here I am giving you the sample paper of the Aptitude test . the test consist the following questions

Solve the following question based on the information provide
i. Students A, B, C, D, E, and F participated in a self-evolution test of Quant‟s and Data (D.I)
ii. Total marls of A in quant‟s was just above C and in D.I just above F was just above C in D.I but he scored less than D in Quant‟s
iii. Got more marks than D and E in D.I but did not perform as well in Quant‟s as in D.I compared to D and E
iv. One is in between C and D in Quant‟s and C and A in D.I
Got the highest make in D.I ?

1) A
2) B
3) C
4)
Data InadequateSolve the following question based on the information provide
i. Students A, B, C, D, E, and F participated in a self-evolution test of Quant‟s and Data (D.I)
ii. Total marls of A in quant‟s was just above C and in D.I just above F was just above C in D.I but he scored less than D in Quant‟s
iii. Got more marks than D and E in D.I but did not perform as well in Quant‟s as in D.I compared to D and E
iv. One is in between C and D in Quant‟s and C and A in D.I
Got the highest make in D.I ?

1) A
2) B
3) C

4) Data InadequateSolve the following question based on the information provide
i. Students A, B, C, D, E, and F participated in a self-evolution test of Quant‟s and Data (D.I)
ii. Total marls of A in quant‟s was just above C and in D.I just above F was just above C in D.I but he scored less than D in Quant‟s
iii. Got more marks than D and E in D.I but did not perform as well in Quant‟s as in D.I compared to D and E
iv. One is in between C and D in Quant‟s and C and A in D.I
Got the highest make in D.I ?

1) A
2) B
3) C

Probability questions

Question 1

In a bus stand, there are two services namely A and B. Every 10 minutes buses will leave from A and this service works from 6.10 am to 2 pm. The service at B starts at 2.20 pm and for every 20 minutes buses will leave from the bus stand. Find the probability of getting bus from service B between 2.20 pm to 2.50 pm, if service A is late by 1 hour.

a) 1/2 b) 1/3 c) 1/4 d) 1/5

Solution :

Usually service A starts at 6.10 am.
Since the service is late by 1 hour, the first and last bus will leave by 7.10 am and 3 pm respectively.
Note that, there is a bus for every 10 minutes.
Number of buses leaving between 2.20 pm to 2.50 pm is 4 and the timings are 2.20 pm, 2.30pm, 2.40pm and 2.50pm.

There is a bus for every 20 minutes from service B.
Number of buses leaving between 2.20 pm to 2.50 pm is 2 and they start at 2.20 pm and 2.40 pm.
Therefore, 4 buses from A and 2 buses from B are available.
The probability of getting bus from B = buses from B / total number of buses from A and B.
= 2/6 = 1/3.

Question 2

From a railway station, trains leave for every 15 minutes and 25 minutes to city A and city B respectively. First train to city A and city B start at 9 am and 10.15 am respectively. If a man arrives to the station in between 11.25 am and 12.25 pm then the probability of getting train for city A is:

a) 1/4 b) 4/7 c) 3/5 d) 2/5

Solution :

The man wants to go to city A and he arrives station in between 11.25 am and 12.25 pm.
First train to city A is at 9 am and there is a train for every 15 minutes.
Trains for city A will leave at the following times : 9 am, 9.15 am, 9.30 am,…,11.30 am, 11.45 am, 12 pm, 12.15pm, and so on.
Number of trains for city A between 11.25 am and 12.25 pm is 4.

First train to city B is at 10.15 am and there is a train for every 25 minutes.
Trains for city B will leave at the following times: 10.15 am, 10.40 am, 11.05 am, 11.30 am, 11.55 am, 12.20 pm, and so on.
Number of trains for city B between 11.25 am and 12.25 pm is 3.
Probability of getting train for city A between 11.25 am and 12.25 pm = Number trains for city A from 11.25 am to 12.25 pm / Total number of trains for city A and B from 11.25 am to 12.25 pm
= 4/7.

Question 3

There are two bus stands, namely X and Y. Buses leave from X for every 30 minutes and its first bus starts at 8.05 am. Every hour number of buses leaving from Y increases by 1 and its first bus starts at 7 am. From Y there is only 1 bus for the 1st hour. Any bus from either of the bus stations takes 15 minutes to reach a nearby bus stop. Suppose a person reaches the stop in between 12.15 pm and 1.15 pm. The probability that the person will get a bus from Y is:

a) 3/4 b) 1/3 c) 1 d) 1/4

Combination questions

Question 1

In a dance school, there are 14 girls and 15 boys. In how many ways, a group consisting of 3 girls and 7 boys can be formed for a competition?

a) 2342340 b) 2232340 c) 2132340 d) 2132840

Solution :

Now, use the combination method, nCr = n! / r! (n-r)!
3 are selected from 14 girls in 14C3 ways = 14! / 3! (14 - 3)! = 14! / 3!11! = 364 ways.
And 7 are selected from 15 boys in 15C7 ways = 15! / 7! (15 - 7)! = 15! / 7!8! = 6435 ways
Hence the required number of possible ways = 364 x 6435 = 2342340 ways.

Question 2

The players for district football team are selected from three different colleges and each college has 5 top players. Except captain and goalkeeper, each 3 are selected from each 3 colleges. Find the number of possible ways of such selection.

a) 1000 b) 1500 c) 4500 d) none of these

Solution :

Total number of players = 11
2 players(captain & goalkeeper)selected in 1 way.
Now, use the combination method, nCr = n! / r! (n-r)!
3 out of 5 can be selected in 5C3 ways = 5! / 3! (5 - 3)! = 10
Similarly, other 3 are selected from other two colleges.
Hence total number of possible ways = 1 x 10 x 10 x 10 = 1000

Question 3

In a college cricket club of 22 players, captain and wicketkeeper are selected from seniors team. For remaining players they have to select from 8 seniors and 12 juniors. Now, for a new team of 11 players except captain and wicketkeeper, out of 9 they select 4 from juniors and 5 from seniors. Find the number of methods to select players of new team.

a) 12220 b) 27720 c) 15870 d) none of these

Puzzele problems

Question 1

Find X's age which equals the number of grand children of a man who has 4 sons and 4 daughters. Each daughter of the man's wife have 3 sons and 4 daughters and each son of the man's wife have 4 sons and 3 daughters.

a) 40 b) 56 c) 64 d) none of these

Solution :

We have to find the number of grand children of the man.
Given that, he had 4 sons and 4 daughters.
Each son has 4 sons and 3 daughters and each daughter has 3 sons and 4 daughters.
Therefore total number of grandsons = 4x4 + 4x3 = 16 + 12 = 28
And total number of grand daughters = 4x3 + 4x4 = 28
Total number of grandchildren is 28+28 = 56.
Hence the required age is 56.

Question 2

A man have many daughters, each daughter have as many sons as her sisters. The product of the number of daughters and grandsons of the man lies between 40 and 50. Find the number of daughters of the man.

a) 6 b) 4 c) 3 d) 8

Solution:

Let N be the number of daughters of the man.
Then each daughter has N-1 sisters.
Given that, each daughter has as many sons as her sisters.
That is, each of them has N-1 sons.

Number of grandsons of the man = N(N-1)
And the required product = N(N-1) x N = N x N(N-1) which lies between 40 and 50.
If N = 1 then N x N(N-1) = 0.
f N = 2 then N x N(N-1) = 2 x 2(1) = 4
If N = 3 then N x N(N-1) = 3 x 3 x 2 = 18
If N = 4 then N x N(N-1) = 4 x 4 x 3 = 48
If N = 5 then N x N(N-1) = 5 x 5 x 4 = 100
Therefore the possible value of N is 4.
Hence the man has 4 daughters.

Question 3

Two men A and B have equal number of daughters and A have 1 more son than B. Each son and daughter of A have 2 sons and 2 daughters and each son and daughter of B have 3 sons and 3 daughters. If A and B have equal number of grandchildren then find the number of sons of B.

a) 3 b) 4 c) 5 d) none of these.

Answer : d) none of these

Solution :

Let D be the number of daughters of A and B.
Let S be the number of sons of A.
Then S-1 be the number of sons of B.

Now, number of grandsons of A = 2S + 2D.
Number of granddaughters of A = 2S + 2D
Number of grand children of A = 2S + 2D + 2S + 2D = 4S + 4D.

Number of grandsons of B = 3(S-1) + 3D = 3S + 3D - 3
Number of granddaughters of B = 3(S-1) + 3D = 3S + 3D - 3
Number of grand children of A = 3S + 3D - 3 + 3S + 3D - 3 = 6S + 6D - 6

And, 4S + 4D = 6S + 6D - 6
2S + 2D = 6
S + D = 3

Then the possibilities of (S,D) are (1,2), (2,1), (0,3), (3,0)
We have to find the value of S-1.
S-1 cannot be a negative number, so (0,3) is not possible.

Therefore, possible S-1 values are 0,1,2.
Hence the answer is option d.
__________________
#8
October 29th, 2015, 10:17 AM
 Unregistered Guest Posts: n/a
Re: Infosys Solved Placement Papers

I want to appear in Infosys Placement exam. So I need sample paper. So here can you provide me a sample paper of this exam?
#9
October 29th, 2015, 10:18 AM
 Super Moderator Join Date: Dec 2012 Posts: 19,443
Re: Infosys Solved Placement Papers

I have a sample paper of Infosys Placement exam. So here I am providing you as you want.
Question 1
An express A starts at 2.30 pm from Karnal station and travel towards Sirsa station at a speed of 80 km per hour. Another express B starts at 4.30 pm from Karnal to Sirsa at the speed of 100 km per hour. How far away from station Karnal will the two trains meet?
a) 400 km b) 100 km c) 800 km d) 450 km
Solution :
Train A starts at 2.30 pm from KARNAL to SIRSA.
Train B starts at 4.30 pm from KARNAL to SIRSA.
Let they meet H hours after 2.30 pm.
We have to find the distance traveled by A in H hours or by B in (H-2) hours.
Given that, speed of A = 80 km/hr
Distance traveled by A in H hours at 80km/hr = (distance = speed x time) = 80H km. … (1)
Speed of B = 100 km/hr.
Note that, it starts at 4.30 pm, that is 2 hours later than A.
Therefore, we would find the distance in (H-2) hours.
Distance traveled by B in (H-2) hours at 100km/hr = 100(H-2) km … (2)
We know that trains meet after H hours and this means distance covered by train A in H hours equals distance covered by train B in H-2 hours.
Therefore, from (1) and (2), we get 80H = (H-2)100
20H = 200
H = 10 hours.
That is, they meet after 10 hours from2.30 pm.
Hence, the required distance = 80H = 80 x 10 = 800 km.
Question 2
A train P starts from Delhi at 8 pm, reaches its destination UP at 1 am. Another train Q starts from UP at 8 pm and reaches Delhi at 2 am. The two trains P and Q will cross each other at :
a) 10.45 pm b) 12.45 pm c) 11.45 pm d) none of these.
Solution :
Let the distance between UP and Delhi be X km.
Time taken by P to reach UP (to cover X km) = 8 pm to 1 am = 5 hours.
Speed of P = distance / time = X/5 km/hr.
Time taken by Q to reach Delhi (to cover X km) = 8 pm to 2 am = 6 hours.
Speed of Q = X/6 km/hr.
Let them meet Y hours after 8 pm.
Distance covered by P at Y hours at X/5 km/hr = XY/5 km
Distance covered by Q at Y hours at X/6 km/hr = XY/6 km.
Since they travel in opposite directions, during the time when they cross each other, the sum of the distance covered by the first and second trains will be equal to the distance between Delhi and destination at UP.
i.e., XY/5 + XY/6 = X
XY (1/5 + 1/6 ) = X
Y (1/5 + 1/6 ) = 1
Y (11/30) = 1
11Y = 30.
Y = 30/11 = 2.72 hours
Therefore, they meet after 2.72 hours from 8 pm.
That is, 8 pm + 2 hours + 45 minutes (nearly).
Hence, the answer is 10.45 pm.
Question 3
Chennai express starts at 8 am from A towards B and Mumbai express starts at 8 am from B towards A. After their meet, Chennai express takes 18 hours to reach B and Mumbai express takes 8 hours to reach A. Then which of the following is their speed’s ratio?
a) 1 : 2 b) 2 : 3 c) 2 : 5 d) 1 : 3
Answer : b) 2 : 3.
Solution :
Note: “ If two trains start at the same time from A and B towards each other and after they take a and b hours in reaching B and A respectively, then
A’s speed : B’s speed = sqrt(b) : sqrt (a).”
Here they start at same time ( 8 am) and travels in opposite direction.
(After their meet), Chennai express takes 18 hours to reach B and Mumbai express takes 8 hours to reach A.
b = 8 and a = 18.
By using the above note, required ratio = sqrt(8) : sqrt(18) = 2 sqrt(2) : 3 sqrt(2) = 2 : 3.
Hence, the answer is 2 : 3.

Paper

1.One guy has Rs. 100/- in hand. He has to buy 100 balls. One football costs Rs. 15/, One Cricket ball costs Re. 1/- and one table tennis ball costs Rs. 0.25 He spend the whole Rs. 100/- to buy the balls. How many of each balls he bought?

2.The distance between Station Atena and Station Barcena is 90 miles. A train starts from Atena towards Barcena. A bird starts at the same time from Barcena straight towards the moving train. On reaching the train, it instantaneously turns back and returns to Barcena. The bird makes these journeys from Barcena to the train and back to Barcena continuously till the train reaches Barcena. The bird finally returns to Barcena and rests. Calculate the total distance in miles the bird travels in the following two cases:
(a) The bird flies at 90 miles per hour and the speed of the train is 60 miles per hour.
(b) the bird flies at 60 miles per hour and the speed of the train is 90 miles per hour

3.A tennis championship is played on a knock-out basis, i.e., a player is out of the tournament when he loses a match.
(a) How many players participate in the tournament if 15 matches are totally played?
(b) How many matches are played in the tournament if 50 players totally participate?

4.When I add 4 times my age 4 years from now to 5 times my age 5 years from now, I get 10 times my current age. How old will I be 3 years from now?

5.A rich merchant had collected many gold coins. He did not want anybody to know about them. One day, his wife asked, "How many gold coins do we have?" After pausing a moment, he replied, "Well! If I divide the coins into two unequal numbers, then 37 times the difference between the two numbers equals the difference between the squares of the two numbers." The wife looked puzzled. Can you help the merchant's wife by finding out how many gold R

6.A set of football matches is to be organized in a "round-robin" fashion, i.e., every participating team plays a match against every other team once and only once. If 21 matches are totally played, how many teams participated?

7.Glenn and Jason each have a collection of cricket balls. Glenn said that if Jason would give him 2 of his balls they would have an equal number; but, if Glenn would give Jason 2 of his balls, Jason would have 2 times as many balls as Glenn. How many balls does Jason have?

8.Suppose 8 monkeys take 8 minutes to eat 8 bananas.
(a) How many minutes would it take 3 monkeys to eat 3 bananas?
(b) How many monkeys would it take to eat 48 bananas in 48 minutes

9.It was vacation time, and so I decided to visit my cousin's home. What a grand time we had! In the mornings, we both would go for a jog. The evenings were spent on the tennis court. Tiring as these activities were, we could manage only one per day, i.e., either we went for a jog or played tennis each day. There were days when we felt lazy and stayed home all day long. Now, there were 12 mornings when we did nothing, 18 evenings when we stayed at home, and a total of 14 days when we jogged or played tennis. For how many days did I stay at my cousin's place?

10.A 31" x 31" square metal plate needs to be fixed by a carpenter on to a wooden board. The carpenter uses nails all along the edges of the square such that there are 32 nails on each side of the square. Each nail is at the same distance from the neighboring nails. How many nails does the carpenter use?

1. F + C + T = 100-------------eq1
15F + C + 0.25T = 100-------------eq2
eq1=eq2 .solve to get F=3T/56 ;F=3,T=56,C=41

2.a) There is no need to consider their meeting pt at all.the train has been running for 90miles/(60miles/hr)=1.5hrs.bird flies till train reaches destination frm strting pt.so bird flies for1.5hrs at the vel given(90).so dist=1.5*90=135miles

b) time of train=1hr.so dist of bird=60*1=60miles

3.(a) u don't need to sum it up.since it's a knock out only 1 person emerges winner finally.so15+1=16is answer.becos after15 matches finally we shud've 15losers and 1winner.

(b) 49:its always one less than no of players as per the idea given above.so no need to check okay cos its always true.ans is 49.

4.Let x= current age
4(x+4)+5(x+5)=10x ;so x=R 41 years

5.37(x-y)=x^2-y^2. u no tht x^2-y^2=(x-y)(x+y).so (x-y) cancels on both sides to give x+y=37.so sum of unequal halves=37 which is the req answer.

6.R ans:7 teams okay.for a match u need 2 teams.suppose there r totally 'n 'teams.
Now uve to choose 2 teams out of 'n' teams.so answer =no of such choices=no. of possible combinations. So we've ans = nC2(ncombination2)=21;solve to get n=7.
Sol: n(n-1)/2=21. so n=7.if u don't understand c the graph below
each team plays no. of matches=no of teams ahead of it. One bar '|' represents one team.
| | | | | | | ------------7
6 5 4 3 2 1 0 -----------21
last team is written as 0 matches becos this team has already played with all other teams-hence sum of matches =6+5+4+3+2+1=21 which is correct only if no of teams =7

7.R 14
1. G+2=j-2
2. 2(G-2)=J+2.
solve these 2 to get
J=14

8.a). Sol:each mky takes 8 min to eat a banana

b).ans:8m=48 m=6

9.Use sets and venn diagram to solve such questions.a,b ,aub,anb etc.
12=tennis+leave
18=jog +leave
so jog-tennis=6
again jog+tennis=14.so solve and get jog=10,leave=8,tennis=4.so tot=22

10.Ans= 32*2 + 30*2=124
__________________
 Other Discussions related to this topic Thread

Message:
Options

 Forum Jump StudyChaCha Discussion Forum     General Topics     Exams     MBA / Business Schools     Study Abroad and Immigration Consultancy     Career and Jobs Questions by Topics     Medicine and Health     Management

All times are GMT +6.5. The time now is 04:11 PM.

 -- Default Style -- Default vBulletin -- Lightweight MBA Discussion - Job Discussion - Contact Us - StudyChaCha - Blog Archives - Forum Archive - Partners : Management Forum Eduvark MBA Forum Courses Forum Top